Check the comments secrtion for a bigger image. Suppose that F = 740 N. If theta

Question

Check the comments secrtion for a bigger image.

Suppose that F = 740 N. If theta = 58 degree and F = 470 N, determine the magnitude of the resultant force. Express your answer to three significant figures and include the appropriate units. Determine the resultant force direction, measured counterclockwise from the positive x axis. Express your answer using three significant figures. Determine the magnitude of the resultant force. Express your answer to three significant figures and include the appropriate units. Determine the direction of the resultant force, measured clockwise from the positive x axis. Express your answer using the significant figures.

Explanation / Answer

part A) F = 470 N

theta= 58 degree

Now , for the magnitude of resultant

FR = sqrt(470^2 + 700^2 + 2 * 700 * 470 * cos(15 + 90 + 90 - 58))

FR = 479.23 N

the resultant force is 479.23 N

part B)

Now , for the direction

(theta) = 58 + arctan(700 * sin(90 + 90 - 58 + 15)/(700 * cos((90 + 90 - 58 + 15)) + 470 ))

solving for theta

theta = 153.02 degree

the direction of net force is 153.02 degree

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for the net force

Fr = sqrt(400^2 + 740^2 + 2 * 400 * 740 * cos(30 + 45))

Fr = 927.8 N

the resultant force is 927.8 N

for the direction

part B)

direction of net force = arctan(400 * sin(75)/(400 * cos(75) + 740)) - 45

direction of net force = -20.4 degree

the direction of net force is -20.4 degree

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