A square conducting slab with 7 m sides camics a net charge of 85 pc. (a) Find t
ID: 1838970 • Letter: A
Question
A square conducting slab with 7 m sides camics a net charge of 85 pc. (a) Find the charge density on each face of the slab and the electric field just outside one face of the slab, o per face AC/m Va67pomroh Maximum number of ammpts for eredit (Fraction oferedit after thr: oto mempt) /16 Maximum tanamber of altempts for credit Fractien of eredi afer that 03up fo attempts) (b) The slab is placed to the right oran infinite charged ing plane that lies in the va plane at r 0. The ebarge density of the infinite ting plane is 1.6 AC m The faces of nonconduct the slab are parallel to the plane. Find the sign and magnitude of the electric field on each side of the slah (far from its edges so edge eflects can be ignored and the chargesensity on each face. E tal right side of slat)- side of slab, between the slab and the sheet) (Fraction ofereditalier 03 to (right side of slab) a (left side of slab) ACm2 67 point, Maxinwan Bumber of attempts creditExplanation / Answer
Here ,
a) for the charge density ,
as charge will be evenly distributed on both faces
charge density = (q/(2* area))
charge density = 85/(2 * 7^2)
charge density = 0.867 uC/m^2
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electric field just outside = charge density/epsilon_0
electric field just outside = 0.867 *10^-6/(8.854 *10^-12)
electric field just outside = 9.79 *10^4 N/C
b) when it is placed on the right to the infinite sheet
electric field (on the right of the slab)
E = 9.79 *10^4 + 1.6 *10^-6/(2 * 8.854 *10^-12)
E = 1.88 *10^5 N/C to the right
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for electric field between the sheet and the slab
E = -9.79 *10^4 + 1.6 *10^-6/(2 * 8.854 *10^-12)
E = -7550 N/C
E = 7550 N/C to the left
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