Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

In a gas turbine experiment air enters the compressor at 77 degree F and 0.2 psi

ID: 1841785 • Letter: I

Question

In a gas turbine experiment air enters the compressor at 77 degree F and 0.2 psig and leaves the compressor at 300 degree F and 21.5 psig, then enters the Turbine at 1290 degree F and 21.3 psig and leaves the Turbine at 1040 degree F and 0.6 psig. The atmospheric pressure is measured as 14.7 psia Determine: The specific work of the compressor The specific heat added to the air through the combustion process The specific work of the turbine The engine actual efficiency Pressure ratio and the Brayton cycle efficiency Turbine isentropic efficiency

Explanation / Answer

1) pressure ratio is calculated. total pressure at inlet 1.027 bar, at outlet 2.496 bar

from gas relations T02'/To1 = (2.496/1.027) ^(k-1/k)

get To2'/To1 = 1.288

outlet temp (actual) is 231.65 F = 110.9C

inlet T=25C

DT = 85.9

Cp DT =work (specific) /kg = 1KJ/Kg K*85.9 = 85.9 KJ/kg

2)Specific heat add to the air thru combustion.

the change in temperature is (1290-300) F = 990F = 550 C=550 K since difference

work done per Kg 550*1 =550 KJ/kg

c) sp work of turbine ,

similar calculation gives T'/T = .783

where inlet temp is 1290F =699C

outlet temp .783*(699+273) = .783*972 =761K

Work CpDT= 1*211 = 211KJ/kg

d) engine actual efficiency. Use actual temps and work and get the ratio

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote