In a gas chromatography experiment, a mixture of two compounds (A and B) was sep

Question

In a gas chromatography experiment, a mixture of two compounds (A and B) was separated for analysis. A chart recorder that fed paper at a constant rate of 100 mm. per minute was used to record the chromatogram, and a mark was made on the chart at the time the sample was injected. The first peak on the chromatogram corresponds to compound A, and that peak was observed at a distance of 4.1 cm from the sample injection point, and it had a height of 3.36 cm and a width at half-height of 1.95 cm. The peak corresponding to B was observed at a distance of 7.51 cm from the injection point, and it had a height of 3.89 cm and a width at half-height of 1.58 cm. What was the retention time for compound B (in seconds)? (Enter your answer as a number only.)

Explanation / Answer

Just take the distance of B from the injection point and convert it into mm by multiplying it by 10. Then divide by 100 to get minutes. The answer looks for in seconds so now multiply this number by 60.
7.51 cm x 10 = 75.1 mm
75.1mm/ 100 mm = .751 min
The retention time for B is

0.751 min x 60 sec = 45.06 sec

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