For Problem 7-86, the heat transfer may be calculated for reversible isothermal

Question

For Problem 7-86, the heat transfer may be calculated for reversible isothermal ideal gas to be mRTln(V2/V1) and the work may be calculated from quasi-equilibrium polytropic relationships to be mRTln((V2/V1). The First Law also says that Q12=W12 What does all this imply for how reversibility relates to isothermal quasi-equilibrium?

of the final pressure for the two cases as the final pressure varies from 1 to 12 kPa. An insulated rigid tank contains 4 kg of argon gas at 45 kPa and 3 degree C. A valve is now opened, and argon is allowed to escape until the pressure inside drops to 2 kPa. Assuming the argon remaining inside the tank has undergone a reversible, adiabatic process, determine the final mass in the tank.

Explanation / Answer

For Problem 7-86, the heat transfer may be calculated for reversible isothermal

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