Five liters (0.006 m3) of liquid H2O at 32 oC and one liter (0.001 m3) of solid

Question

Five liters (0.006 m3) of liquid H2O at 32 oC and one liter (0.001 m3) of solid H2O ice at -32 oC are sealed in
a flexible, perfectly insulated container. The ice is in a plastic bag so the masses do not mix. After some
time elapses thermal equilibrium is achieved. The mass and energy of the container and plastic wrap are
negligible. The internal pressure is constant at local atm. pressure of 100 kPa.
NOTE: Moderate pressure
(<100 bar) has little effect on liquids and solids. So, properties of solid or liquid cooled below the saturation
temperature are approximately those on the saturation line at the material temperature. (This saturation state
will be at low pressure.) Find the final temperature (oC), volume (m3) and total work (kJ) of the H2O.
Show a State Table and sketch a graph of temperature versus time showing the temperatures of the
liquid water and the

Explanation / Answer

heat lost by water = heat gained by ice
the above eqn will give final temp
if final temp is below 0o find volume of ice formed using 1st eqn, remaining is volume of water.

total work =pv

v= final-initial volume of water

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.