FIGURE 4.38 Using the bottom node as reference, determine the voltage across the

Question

FIGURE 4.38 Using the bottom node as reference, determine the voltage across the 5 Ohm resistor in the circuit of Fig. 4.39, and calculate the power dissipated by the 7 Ohm resistor. FIGURE 4.39

Explanation / Answer

12 = i_1+5+i_7 =>i_1+i_7 = 7.......(1) i_1 = 4+i_5 i_4 = 5+i_7 i_5+i_4 = 8 =>i_5+5+i_7 = 8 =>i_5+i_7 = 3 i_1+i_5 = 4......(i) =>i_5 = 4-i_1 =>4-i_1+i_7 = 3 =>i_1-i_7 = 1......(2) Solving (1) and (2) we get, i_1 = 4A, i_7 = 3A Substitute i_1 in (i) to get, 4+i_5 = 4 =>i_5 = 0 =>Voltage across 5ohm resistor = 0 Power dissipated by 7 ohms resistor = i_7^2*7 = 9*7 = 63W

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