A soap bubble of diameter 24.50 mm is filled with air. The absolute pressure out

Question

A soap bubble of diameter 24.50 mm is filled with air. The absolute pressure outside the bubble is 100.5 kPa. The gage pressure inside the bubble is 15.90 Pa. The temperature both inside and outside of the bubble is 20.00degreeC. Give all answers to 4 significant digits. Calculate the absolute pressure in kPa inside the bubble. Compare to the pressure outside the bubble and discuss. Calculate the density of the air inside and outside the bubble. Compare and discuss. Calculate the surface tension of the soapy water and compare to that of pure water at the same temperature. Discuss.

Explanation / Answer

Inside absolute pressure = outside pressure + gage pressure = 100.5+0.0159 = 100.5159 kPa

b) Density can be found using ideal gas equation,
PV= nRT , dividing both sides by V
P =RT ( is density and R is specific gas constant)

c) Excess pressure in bubble = 4/r

=surface tension,

so 15.90 =4*/ 0.01225

= 0.04869375 N/m

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