mead. Use the cross explained in Question 20 to answer questions 20-23 20 In fru
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Question
mead. Use the cross explained in Question 20 to answer questions 20-23 20 In fruit flies, gray body is dominant over ebony body, and long short wing. A male fruit fly, heterozygous for gray with a female fruit fly with ebony body and homozygous for long wings. What is the P wings are dominant over body and having short wings is crossed generation? C. Ggll x gELL D. Ggll x ggll 21.- What is the probability of producing an offspring with the genotype Ggli? A, 0% B. 25% C. 50% D. 100% 22 What is the probability of producing an offspring with the genotype 8Lu? A.096 B. 25% C. 50% D. 100% 23.-- what is the probability of producing an offspring with the genotype GgLL? A.096 B. 25% C. 50% D. 100%Explanation / Answer
20.Correct answer is: C.Ggll * ggLL
Reason: Heterozygous gray means both dominant and recessive alleles are present while homozygous recessive/dominant means both the alleles are either recessive or dominant respectively.
Let us cross Ggll *ggLL to get all the answers from 21-23.
Ggll :gametes will be :Gl,GI,gI,gl
ggLL :gametes will be : gL,gL,gL,glL
21.From the punnet square above , we can say 21 labelled i.e GgLl are 8 in number.So, probability is 8/16* 100 = 50%.Correct answer is :C.50%
22..From the punnet square above , we can say 22 labelled i.e ggLl are 8 in number.So, probability is 8/16* 100 = 50%.Correct answer is :C.50%
23..From the punnet square above , we can say GgLL is not present.So, probability is 0.Correct answer is :A.0%
gL gL gL gL Gl GgLl 21 GgLl 21 GgLl 21 GgLl 21 Gl GgLl 21 GgLl 21 GgLl 21 GgLl 21 gl ggLl 22 ggLl 22 ggLl 22 ggLl 22 gl ggLl 22 ggLl 22 ggLl 22 ggLl 22Related Questions
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