an air standard brayton cycle has inlet conditions of 540 R and 14 .7 psia, a co

Question

an air standard brayton cycle has inlet conditions of 540 R and 14 .7 psia, a compressor efficiencyof 85.86%, and a compressor ratio of 10.23. the turbine inlet temp is 2800r and the actual turbine exhaust temp is 1750 r. the turbine wxhaust pressure is 15.237 psia.

find

isentropic compressor outlet enthalpy

actual compressor outlet enthalpy ant temp

actual compressor work

heat added in the source of the combustion chamber

isentropic turbine exhaust enthalpy

the actual turbine work

net work

and cycle efficiency

Explanation / Answer

T1=540 R=300K

P1=14.7 psi

(note-1R=0.555K

1KJ=0.9478 btu)

(T1/T2)=(P2/P1)^1-1.4/1.4

300/T2=(10.23)^-0.4/1.4

T2=583.09 K

0.8586=T2-T1/(T2*-T1)

T2*=629.71 K

P3=P2=P1*10.23=150.381 psi

p3/p4=9.8694

T3/T4=(P4/P3)^1-1.4/1.4

T4=808.75 K

1)h1=cp*T2=1.005*583.09=586.005KJ=555.41 BTU

2)h1(ACTUAL)=cp*T2*=1.005*629.71=632.85KJ=599.82 BTU

T2=583.04K=1049.57R

3)WC=CP(T2*-T1)=331.358KJ=314.06 BTU

4)Q=CP(T3-T2)=930.47 KJ=881.90 BTU

5)T4=808.75 K=1457.20R

6)WT=CP(T3-T4)=628.2061KJ=591.41 BTU

7)Wnet=WT-WC=281.35 BTU

8)effeciency=Wnet/Q=31.9%

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