Please see the attached picture. Any help is appreciated. The circular disk rota

Question

Please see the attached picture. Any help is appreciated.

The circular disk rotates about its center O. For the instant represented, the velocity of A is vA = -4.9j in./sec and the tangential acceleration of B is (aB)t = -6.3i in./sec2. Write the vector expressions for the angular velocity omega and angular acceleration a of the disk. Use these results to write the vector expression for the acceleration of point ac of point C. Answers: omega = ( i + j + k)rad/sec a = ( i + j + k)rad/sec2 ac = ( i + j + k)in./sec

Explanation / Answer

w = (v cross r)/r^2 =- 4.9/5.2 k=0i +0j -0.942 k

a = (a cross r)/r^2 = -6.3/5.2 = 0i+0j+1.212 k

centrifugal accelaration (Ac)= v^2/r = 4.9^2 / 5.2 = 4.617

Ac = (Atsin47 - Accos47) i + ( Ac sin47 +Atcos47) j +0k = 1.458i +7.6734 j +0 k

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