Question
Answer Part C & D
To use the dot product to find the components ot forces acting in arbitrary directions. A three-legged structure is shown below. It is attached to the ground at points B = (3.10, 0,0) and C = (-3.10, 0, 0) and connected to the ceiling at point A = (-4.26, 4.24, 5.39). The three legs connect at point D = (0, 3.35, 3.00), where two forces, F and P, act. Force F is given by F = 5.00 i - 20.0 j + 29.2 k N; P has magnitude 50.0 N and direction angles alpha = 147.5 degree beta = 87.0 degree , and 7 = 60.0 degree for the x, y, and z axes, respectively. Determining the force along a member Determine the magnitude, Fda, acting along member DA, due to the applied force F = 5.00 i-20.0j + 29.2 kN. Express your answer to three significant figures and include the appropriate units. Finding the component of a force perpendicular to a direction Given F = 5.00 i - 20.0 j + 29.2 kN, find the component of F that acts perpendicular to member DA such that the vector addition of the perpendicular and parallel components of F (F = Fj + Fn) with respect to DA equals F. Express your answer in component form. Express your answers, separated by commas, to three significant figures.
Explanation / Answer
a. 5
b. sqrt(20^2+29.2^2)=35.39
