(5) In a given lightning flash, the potential difference between a cloud and the

Question

(5) In a given lightning flash, the potential difference between a cloud and the ground is 1.43 x 109 V and the quantity of charge transferred is 26.9 C What is the decrease in energy of the transferred charge? (Please give the magnitude.) If all that energy could be used to accelerate a 1131 kg automobile from rest, what would be the final speed of the automobile? 06.01 x 0 8.25 x 103m/s 2O 7.69 x 1010J 8.25 x 103 m/s 3. O 3.84 x 1010 J; 8.25 x 103 m/s 4. O 3.84 x 1010 J; 10.79 x 103 m/s 5. O 6,01% 100 J; 4.12 x 103 m/s

Explanation / Answer

here,

potential difference , V = 1.43 *10^9 V

Q = 26.9 C

decrease in energy of the charge = Q * V

decrease in energy of the charge = 26.9 * 1.43 *10^9

decrease in energy of the charge = 3.84 *10^10 J

Now, for the speed

0.50 * 1131 * u^2 = 3.84 *10^10

solving for u

u = 8.25 *10^3 m/s

hence , the correct option is 3)

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