C Chapter 19 Problems, Se x CAn Empty Paralel Platec C Capacitor AAns Capacit. x
ID: 1864340 • Letter: C
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C Chapter 19 Problems, Se x CAn Empty Paralel Platec C Capacitor AAns Capacit. xG ho to add more quesio x CSecure https://www VAssignment t'dep 18888883 3 days remaining In your frec tra Chapter 19 Problems, Section 19.1-19.3 (Homework) Incructor: B Brian 3chut :Monay, Jsty 9 2010 08 20 AW Exdension Requests' Princ Assignnen Ponts Foth?ase gnment ycu submit answers by quesson parts. The number of Submiseans remaling tor each question part only chanDes you submit or change the answer Assianment Scoring Your kast s My Nooes Ash Your tial slit erens ? b t een a cle d and the ground is 2.00 X 10? ith th-claud being at th higher tnitential wh is th change in a Hlect nn k lettric potential energy hen the elect an moves fr m nie gro und ta th urin partit dar thunderst ann, the electric tot 10-11 X 1 Additional Natenals cl ud o n loud la telev sion cture t be clectrons strike the screen ? er ben? accelerated from rest t rough ? potertial difference o 24?50 Y. The speeds o the dec rons re quite large and for accurate calculatona o the speeds the suth elTects, find te eletron ejust bo eletron strikeste se fects o 2pecial relativ tr must be taken into account. Igro ng Addltional Naterials O Type here to search 1135 PM 8/2018Explanation / Answer
the change in the electron’s electric potential energy when the electron moves from
the ground to the cloud is
del U = q del V
= (-1.6* 10^-19) (2.0* 10^5 )
=-3.2* 10^-14 J
(b)
Apply conservation of energy
W= 1/2 mv^2
q del V = 1/2 m v^2
v = sqrt 2 q del V/m
= sqrt 2 (1.6* 10^-19) (24950)/9.11* 10^-31
= 93.61* 10^6 m/s
=9.36* 10^7 m/s
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