A 6.31 kg particle is subjected to only conservative forces and its potential en

Question

A 6.31 kg particle is subjected to only conservative forces and its potential energy diagram is shown below Use the diagram to find the maximum velocity of the particle between points C and G. At point H the particle has a speed of 14.5 m/s 1100 ntial Energy (J) 600 100 0 0 10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 190 200 x position (m) Between points C and G at what location is the particle moving the fastest? O The particle is moving at the same speed at all of the points listed here SCROLL DOWN FOR MORE

Explanation / Answer

Solution:

velocity will be maximum when the object particle will have least potential energy.

and between C and G , D is the point of least potential energy.

Hence particle will be moving fastest at point D

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Using conservation of energy

total energy at point H = total energy at point D

=> 300 + 0.5 * 6.31 * 14.5 * 14.5 = 200 + 0.5 * 6.31 * v^2

=> v = 15.6 m/s (three significant digits)

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