During a neighborhood baseball game in a vacant lot, a particularty wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularty wild hit sends a 143-g basbal crashing through the pane of a second-floor window in a nearby búilding. The ball strikes the glass at 11.9 m/s, shatters the glass as it passes through, and leaves the window at 8.09 m/s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball? The direction of the O ball's motion site the direction of the ball's motion 19 O Neither of these Calculate the magnitude of this impulse (a positive number). Number The ball is in contact with the glass for 10.5 ms as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number). Number

Explanation / Answer

a) opposite the direction of the ball's motion

b) magnitude of impulse = |m*(v2- v1)|

= |0.143*(8.09 - 11.9)|

= 0.545 N.s

c) we know, Impulse = F_avg*delta_t

use, F_avg*delta_t = Impulse

==> F_avg = Impulse/delta_t

= 0.545/(10.5*10^-3)

= 51.9 N

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