During a neighborhood baseball game in a vacant lot, a particularly wild hit sen

Question

During a neighborhood baseball game in a vacant lot, a particularly wild hit sends a 0.142-kg baseball crashing through the pane of a second-floor window in a nearby building. The ball strikes the glass at 15.5 m / s, shatters the glass as it passes through, and leaves the window at 10.3 m / s with no change of direction. What is the direction of the impulse that the glass imparts to the baseball?

Calculate the magnitude of this impulse (a positive number).

The ball is in contact with the glass for 0.0107 s as it passes through. Find the magnitude of the average force of the glass on the ball (a positive number).

Explanation / Answer

impulse = change in momentum => J = m*(Vf - Vi) => J = 0.142*(10.3 -15.5) = -0.7384 N-s -ve sign shows that the direction of impulse is in the opposite direction as that of velocity of ball. magnitude of impulse = 0.7384 N-s F*t = 0.7384 => F = 0.7384/0.0107 = 69 N

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