HW 2 Ch 17 Winter 2018 Adaptive Follow-Up Item 4 Problem 17.41 Find thezand y co

Question

HW 2 Ch 17 Winter 2018 Adaptive Follow-Up Item 4 Problem 17.41 Find thezand y components of the electric field at z=0.150m. y=-0450 m In a rectangular coordinate system, a positive point charge q 2.50 nC is placed at the point z = 0.150 m,y 0, and an identical point charge is placed at z =-0.150 m ,y=0, Find the z and y components and the magnitude and direction of the electric field at the following points N/C Submit Request Answer Part G Find the magnitude of the electric field at z=0150m,y= 0.450 m High School Diploma The Legend of ch 01 lecture s Zelda ..Q mp3 p16 notes.pdt MacBook Air 0 F) F5 FT

Explanation / Answer

formula for electric field due to point charge is

E = k q/ r^2

from the pythogorus theorem

s= sqrt ( 0.3)^2 + ( 0.450)^2 = 0.54 m

sin theta = 0.450/0.54 = 0.833

cos theta = 0.3/0.54 = 0.555

E1y = k q1/ r^2 = 9 * 10^9 ( 2.5 * 10^-9)/(0.450)^2 = 111.11 N/C ( -j)

E1x = 0

E2 x = k q2/ s^2 * cos theta =9 * 10^9) ( 2.5* 10^-9)/( 0.54)^2 * 0.555 = 42.82 N/C i

E2y =  k q2/ s^2 * sin theta =9 * 10^9) ( 2.5* 10^-9)/( 0.54)^2 * 0.833 = 64.27 N/C ( -j)

Ex = E1 x+ E 2x = 0 + 42.82 N/C i

Ey = E1y + E2y =- 111.11 N/C-64.27 N/C = -175.38 N/C j

(b)

magnitude

E = sqrt Ex^2 + Ey^2 = sqrt ( 42.82)^2 + ( -175.38)^2 = 18.53 N/C

sin theta = 0.450

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