1-)A small charged sphere is attached to a thread and placed in an electric fiel

Question

1-)A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that the sphere is in a static situation when placed in the field. If the thread is horizontal, find the magnitude and direction of the electric field. The sphere has a mass of 0.05 kg and contains a charge of + 3.0 x 103 C. Show your work and/or explain your reasoning.

2-)Now the same particle is removed from the thread and placed over the center of a charged plate. Are there any conditions under which it is possible for the particle to be suspended in the air above the plate? Show any relevant calculations and explain your reasoning.

Explanation / Answer

1)

IN static situation net force = 0

Fnet = 0

Fe + Fg = 0

Fg = gravitational force = -m*g ( downwards)

Fe = E*q

E*q - m*g = 0

E*q = m*g

E = m*g/q

E = (0.05*9.8)/(3.3*10^3)

E = 1.48*10^-4 N/C

magnitude of electric field E = 1.48*10^-4 N/C

direction = upwards

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2)

If the charged plate is positive , then the electric field abouve the plate is upwards

electric force F = Eq act in upwards direction

If Eq = mg

the particel will remain suspended in air

the electric field of the plate should be equal to E = 1.48*10^-4 N/C

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