Question 1 e The electric field in a region of space can be expressed by (195m(0

Question

Question 1 e The electric field in a region of space can be expressed by (195m(01 + 1.50x10-rm1+ 561M(NG. If a circle of diameter 15.0 cm is placed in the xz-plane of this region, what will be the electric flux through the circle? 9.91 N m2/c O 26.5 N m2ic O 28.5 N m2/c O 3.45 N m2ic the circder Question 2 The flux through a hexagonal prism is -1.24x103 Nm2/C. What is the charge inside the hexagonal prism? -58.5 C O -1.13x103c O -1.10x10-8 c O 1.24x103 Question 3 The electric field just above the face of a penny is 1.51x103 N/C. What is the surface charge density on the surface of that penny face? 1.01x106 C/m2 O5.86x10-15 cm2 O 1.34x10-8 C/m2

Explanation / Answer

E = 195 i + 1500 j + 561 k N/C

A = pi (0.15/2)^2 j = 0.0177 j

flux = E.A = (1500 x 0.0177) = 26.5 N m^2 / C ....Ans

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net flux = Qin/ e0

Qin = (-1.24 x 10^3)(8.854 x 10^-12)

= - 1.10 x 10^-8 C .......Ans

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E = sigma / e0

sigma = (1.51 x 10^3) (8.854 x 10^-12)

= 1.34 x 10^-8 C/m^2

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