(16%) Problem 4: Consider ten 260 resistors connected together. 50% Part (a) wha

Question

(16%) Problem 4: Consider ten 260 resistors connected together. 50% Part (a) what would be their resistance, Rs, in kilohms, if they were connected in series? Grade Summa Deductions Potential 0%, 100% - cos0 cotanasin acos0 tan acotan inho cosh0 tanh cotanh) sin0 Submissions Attempts remaining: 10 (3% per attempt) detailed view 4 5 6 0 Degrees O Radians Submit Hint Hints: 1% deduction per hint. Hints remaining: Feedback: 0% deduction per feedback. - -50% Part (b) what would be their resistance, Rp, in ohms, if they were connected in parallel?

Explanation / Answer

if they were connected in series

then

Req = R1 + R2 + R3 + R4 + ............+ R10

R1 = R2 = ................ = R10

so

Req = 260 ohm = 10R5

R5 = 26 ohm

if they were connected in parallel

1/Req = 1/R1 + 1/R2 + 1/R3 ............ + 1/R10

but

R1 = R2 = R3 ..................= R10

so

1/260 = 1/Rp +1/Rp + .................

1/260 = 10/Rp

Rp = 2600 ohm

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