Let us consider a spherical convex refracting surface and curvature radius R = 2

Question

Let us consider a spherical convex refracting surface and curvature radius R = 2 m. We place the object in front of this surface in the distance s = 4 m, and the position of the image is s = 8 m on the right s we saw in our derivation of the lensmaker equation, it is possible that the devices can be too close Spherical Refracting Surface (1) do a ray trace, because the image of the first device is not on the incoming side of the second device from the surface. The refraction index of the air is n1 = 1. A.) What is the refraction index, n2, of the meterial on the right from the surface? B.) What is the magnification? Is the image upright or inverted?

Explanation / Answer

Given,

R = 2m ; s = 4 m ; s' = 8 m ; n1 = 1

a)We need to find n2

We know that

n2/s' - n1/s = (n2 - n1)/R

n2/8 + 1/4 = (n2 - 1)/2

n2 + 2 = 4 n2 - 4

n2(4 - 1) = 2 + 4 = 6

n2 = 6/3 = 2

Hence, n2 = 2

B)Magnification is given by:

M = -s'/s x n1/n2

M = 8/-4 x 1/2 = -1

Hence, M = -1

The image is inverted since M is negative.

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