Question 2 An electron is accelerated from rest between two parallel plates that

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Question 2 An electron is accelerated from rest between two parallel plates that are seperated by 3.10 cm. The potential difference between the two plates is 4.47x103 V. If the electron travels from the negative plate to the positive plate, what will be the speed of the electron as it exits through a small hole in the positive plate? 6.98x106 m/s 3.10x107 m/s 3.96x107 m/s 4.82x107 m/s Question 3 C2 C: What is the equivalent value of the capacitance for the figure shown? C,-23.0 F, C2-10.0 F and C3-29.0 F. O 5.62 F 15.4 HF O 62.0 F

Explanation / Answer

(2)

Given that,

d = 3.10 cm

V = 4.47*10^3 V

Here, electric potential energy = KE of electron

qV = (1/2)mv^2

1.6*10^(-19)*4.47*10^3 = (1/2)*9.1*10^(-31)*v^2

v = 3.96*10^7 m/s

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