=ma t F 9 --FBA 3. A rescue helicopter wants to drop a package (vyo 0 for the pa

Question

=ma t F 9 --FBA 3. A rescue helicopter wants to drop a package (vyo 0 for the package) to isolated mountain climbers on a rocky ridge 200 (m) below as shown in figure (a). If the helicopter is traveling horizontally with a speed of vxo 45 (m/s), how far in advance (horizontal distance) must the package be dropped? If instead the same helicopter is a horizontal dis tance of 400 (m) in advance of the climbers as shown in figure (b), what vertical velocity should the package be given (up or down) so that ft arrives exactly at the climbers? Thrown upward? "Dropped" So=0) 200 m Thrown downward? 200 m 400 m

Explanation / Answer

A)

time taken by packet to drop = sqrt (2h/g)

t = sqrt (2*200/9.8) = 6.389 s

Distance =vt = 45 m/s x 6.389 sec

d = 287.505 m

B)

time taken = 400/45 = 8.89 s

Using second equation of motion,

H = ut + 0.5gt^2

200 = 8.89u + (0.5 x 9.81 x 8.89^2)

u = -21.1 m/s

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