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> 49 4. A statistics professor conducts an experiment to compare the effectivene

ID: 3266233 • Letter: #

Question

> 49 4. A statistics professor conducts an experiment to compare the effectiveness of two methods of teaching his course. Method l is the usual way he teaches the course: lectures, homework assignments, and a final exam. Method Il is the same as method I, except the students receiving method Il get 1 additional hour per week in which they solve illustrative problems under the guidance of the professor. Since the professor is also interested in how the methods affect students of differing mathematical abilities, volunteers for the experiment are subdivided according to mathematical ability into superior, average, and poor groups. Five students from each group are randomly assigned to method I and five students from each group to method Il. At the end of the course, all 30 students take the final exam. Scores are the number of points received out of a total of 50 possible points. The final exam scores are shown below. (25 points):

Explanation / Answer

Solution

This is a case of ANOVA 2-way classification with equal number of observations per cell.

Back-up Theory

Suppose we have data of a 2-way classification ANOVA, with r rows, c columns and n observations per cell.

Let xijk represent the kth observation in the ith row-jth column, k = 1,2,…,n; i = 1,2,……,r ; j = 1,2,…..,c.

Then the ANOVA model is: xijk = µ + i + j + ij + ijk, where µ = common effect, i = effect of ith row, j = effect of jth column, ij = row-column interaction and ijk is the error component which is assumed to be Normally Distributed with mean 0 and variance 2.

Now, to work out the solution,

Terminology:

Cell total = xij. = sum over k of xijk

Row total = xi..= sum over j of xij.

Column total = x.j. = sum over i of xij.

Grand total = G = sum over i of xi.. = sum over j of x.j.

Correction Factor = C = G2/N, where N = total number of observations = r x c x n =

Total Sum of Squares: SST = (sum over i,j and k of xijk2) – C

Row Sum of Squares: SSR = {(sum over i of xi..2)/(cxn)} – C

Column Sum of Squares: SSC = {(sum over j of x.j.2)/(rxn)} – C

Between Sum of Squares: SSB = {(sum over i and jof xij.2)/n} – C

Interaction Sum of Squares: SSI = SSB – SSR – SSC

Error Sum of Squares: SSE = SST – SSB

Mean Sum of Squares = Sum of squares/Degrees of Freedom

Degrees of Freedom:

Total: N (i.e., rcn) – 1;

Between: rc – 1;

Within(Error): DF for Total – DF for Between;

Rows: (r - 1);

Columns: (c - 1);

Interaction: DF for Between – DF for Rows – DF for Columns;

Fobs:

for Rows: MSSR/MSSE;

for Columns: MSSC/MSSE;

for Interaction: MSSI/MSSE

Fcrit: upper % point of F-Distribution with degrees of freedom n1 and n2, where n1 is the DF for the numerator MSS and n2 is the DF for the denominator MSS of Fobs

Significance: Fobs is significant if Fobs > Fcrit

Calculations:

Excel Calculations

r

3

c

2

n

5

N

30

i

j

xijk; k =

xij.

Xijk square

sum

xij. square

Row sum

xi..

Row sum

sq/cn

Col sum

x.j.

1

2

3

4

5

1

1

39

41

48

42

44

214

9206

45796

448

20070.4

585

2

49

47

47

48

43

234

10972

54756

634

2

1

43

36

40

35

42

196

7734

38416

411

16892.1

49612.07

2

38

46

45

42

44

215

9285

46225

3

1

30

33

29

36

47

175

6335

30625

360

12960

2

37

41

34

40

33

185

6895

34225

Excel Summary

G

1219

C

49532.03

Sumxijk^2

50427

Sumxij.^2

250043

Sumxi..^2

49922.5

Sumx.j.^2

49612.07

SST

894.9667

SSB

476.5667

SSR

390.4667

SSC

80.03333

SSI

6.066667

SSE

418.4

ANOVA TABLE

Source

DF

SS

MSS

Fobs

Fcrit

Row

2

390.4667

195.2333

11.19885

3.402826

Column

1

80.03333

80.03333

4.590822

4.259677

Interaction

2

6.066667

3.033333

0.173996

3.402826

Between

5

476.5667

95.31333

Error

24

418.4

17.43333

Total

29

894.9667

30.86092

Since Fobs > Fcrit, for row and column, at 5% level of significance, both row effect and column effect are significant => we conclude that teaching method has an effect on the test score and the average scores of the three groups of students are significantly different.

However, since Fobs < Fcrit, interaction effect does not exist.

r

3

c

2

n

5

N

30

i

j

xijk; k =

xij.

Xijk square

sum

xij. square

Row sum

xi..

Row sum

sq/cn

Col sum

x.j.

1

2

3

4

5

1

1

39

41

48

42

44

214

9206

45796

448

20070.4

585

2

49

47

47

48

43

234

10972

54756

634

2

1

43

36

40

35

42

196

7734

38416

411

16892.1

49612.07

2

38

46

45

42

44

215

9285

46225

3

1

30

33

29

36

47

175

6335

30625

360

12960

2

37

41

34

40

33

185

6895

34225

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