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The flash unit in a camera uses a special circuit to \"step up\" the 3.0 V from

ID: 1872837 • Letter: T

Question

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 270 V ,which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 s , and the average power dissipated in the flashlamp is 1.0×105 W .

Part A

What is the capacitance of the capacitor?

The flash unit in a camera uses a special circuit to "step up" the 3.0 V from the batteries to 270 V ,which charges a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 10 s , and the average power dissipated in the flashlamp is 1.0×105 W .

Part A

What is the capacitance of the capacitor?

Explanation / Answer

energy stored is U = 0.5*C*V^2 = Power* time taken

U =0.5*C*V^2 = 1*10^5*10*10^-6 = 1 J

then

0.5*C*V^2 = 1

0.5*C*3^2 = 1


C = 0.222 F

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