15. A 120 kg individual is on top of a scale in an elevator as the elevator goes

Question

15. A 120 kg individual is on top of a scale in an elevator as the elevator goes upwards. As the elevator approaches its destination, it decelerates by 4 m/s2 to eventually halt. What is the individuals weight as the elevator is decelerating? 16. You are on the highest point on a Ferris wheel which is 50m tall. You toss a tennis ball upwards and its speed is 40 m/s. you forget you tossed the ball and it falls to the ground below without any interruption. How fast does the tennis ball move as it hits the ground?

Explanation / Answer

(15) solution) mass m=120 kg

deceleration a=4m/s^2

If the elevator is moving up then weight w=m(g+a)

w=120(9.8+4)

w=1656N

But weight when coming down is w=m(g-a)

w=120(9.8-4)

w=696N

16) initial velocity u=40m/s

Height h=50m

V^2 =U^2- 2gh

V^2=(40)^2 - (2×9.8×50)

V=24.89m/s

V=25m/s approximately

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.