amics An Engine+ ownloads/Thermo/Exam%201%20Solution.pdf Cieany malk your cnoice

Question

amics An Engine+ ownloads/Thermo/Exam%201%20Solution.pdf Cieany malk your cnoice ana answer. Unless stated differently, you may use the room temperature, constant specific heat Do not interpolate property tables. Use the closest entry in the table instead. The formal work and heat sign convention apply to all answers s model for any ideal gases occurring in the questions below (1) A rigid tank consists of two compartments separated by a partition. One is initially filled with 1.5 kg of air at a pressure of 500 kPa and temperature of 227 °C. The other compartment is initially completely evacuated and has a volume of 0.5 m. The partition between them is now removed and the air now completely fills both compartments of the tank. The final pressure is 200 kPa. sve 42o5 A. What is the initial volume of air in this tank? v - 28,97 (500) 0.001641 m -b. 0.1078 m3 C 0,4305 m3 d. 0.5621 m3

Explanation / Answer

28.97 is the molar mass of air.

Here is the solution,

Using ideal gas law,

PV=nRT

where p is pressure, V is volume, n is the number of moles, R is the gas constant, T is the temperature

we can write, n= m/M

where m is the given mass and M is the molar mass (which is 28.97 in this case)

V= mRT/(PM)

= 1.5*8.314*500/(28.97*500)

V= 0.4305 m3

If you have any furthur doubts do comment.

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