9. 6/9 points | Previous Answers My Notes Two skaters, each of mass 50 kg, appro
ID: 1875098 • Letter: 9
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9. 6/9 points | Previous Answers My Notes Two skaters, each of mass 50 kg, approach each other along parallel paths separated by 2.0 m. They have equal and opposite velocities of 2.2 m/s. The first skater carries one end of a long pole with negligible mass, and the second skater grabs the other end of it as she passes. Assume the ice is frictionless. (a) After they become connected by the pole, what is the distance from each skater to the axis of rotation? 1.00 (b) What is their angular velocity? 2.20 (c) By pulling on the pole, the skaters reduce their separation to 0.7 m. What is their angular speed then? 6.2857 rad/s X rad/sExplanation / Answer
a) r = l/2
r = 2m/2 = 1 m
b) w = v/r = 2.2/1 = 2.2 rad/s
c) from conservation of angular momentum
I1W1 = I2W2
2mr^2*v/r = 2mr'^2*w2
w2 = rv/r'^2
r = 1m and r' = 0.7 m
w2 = 1*2.2/0.7^2 = 4.49 rad/sec
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