Consider a point on the CD that is halfway between its center and its outer rim.

Question

Consider a point on the CD that is halfway between its center and its outer rim. Without repeating all of the calculations required for part A, determine the linear speed at this point Express your answer using three significant figures. A compact disk with a 12.0-cm diameter is rotating at 36.0 rad/s. m/s Submit Request Answer Part D Without repeating all of the calculations required for part B, determine the centripetal acceleration at the point in part c. Express your answer using three significant figures m/s2 Submit

Explanation / Answer

"what is the linear speed? in M/S"

The linear speed depends on where you are on the disk.

v = *r

so if we are on the edge, where r = d/2 = 6.0 cm = 0.060 m,

v = 36rad/s * 0.060m = 2.16 m/s

"what is the centripetal acceleration of a point on its outer rim? in m/s^2"

centripetal a = ²r = (36)² * 0.060m = 77.76 m/s²

C)

"Consider a point on the CD that is a quarter of the way from the center to the outer rim. Without repeating all of the calculations required for parts (a) and (b), determine the linear speed of this point. In m/s"

Observe that the linear speed is proportional to the radius, so at ¼ the radius, we have ¼ of the edge's linear velocity.

v' = 2.16 / 4 = 0.54 m/s

D)

"Determine the centripetal acceleration of this point. in m/s^2"

centripetal acceleration is proportional to radius, so again at ¼ r we have ¼ a:

a' = 77.76/ 4 = 19.44 m/s²

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