A proton accelerates from rest in a uniform electric field of 640 N/C. A moment

Question

A proton accelerates from rest in a uniform electric field of 640 N/C. A moment later, its speed is 1200 km/s. a. Determine the acceleration of the proton b. Determine the distance that it travels A proton accelerates from rest in a uniform electric field of 640 N/C. A moment later, its speed is 1200 km/s. a. Determine the acceleration of the proton b. Determine the distance that it travels A proton accelerates from rest in a uniform electric field of 640 N/C. A moment later, its speed is 1200 km/s. a. Determine the acceleration of the proton b. Determine the distance that it travels

Explanation / Answer

(A) a = Fe / m = q E / m

a = (1.6 x 10^-19)(640)/(9.109 x 10^-31)

a = 1.124 x 10^14 m/s^2

(B) vf^2 - vi^2 =2 a d

(1200 x 10^3)^2 - 0 = 2(1.124 x 10^14)(d)

d = 6.4 x 10^-3 m or 6.4 mm

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