Two Accelerating Particles Points:2 Two point-like particles are placed 42.5 cm

Question

Two Accelerating Particles Points:2 Two point-like particles are placed 42.5 cm apart and are given equal and opposite charge. The first particle, of mass 31.2 g, has an initial acceleration of 8.35 m/s2 towards the second particle. What is the mass of the second particle if its initial acceleration towards the first is 4.05 m/s2 6.43x101 g ou are correct. Your receipt no. is 154-7369 Previous Tries What is the magnitude of the charge on each particle? 6174E-6G Submit Anseer Tries 2/5 Previous Tries This discussion is closed. send Feedback

Explanation / Answer

According to the concept of the electric charges and fields

F=kq/r^2

given that

distance r=0.425 m

mass of first paraticle m1=31.2 g

acceleration of the first paraticle a1=8.35 m/s^2

mass of the second paraticle M2=64.3 g

acceleration of the second paraticle a2=4.05 m/s^2

now we find the both charges

m1a1=kq^2/r^2

31.2*10^-3*8.35=9*10^9*q^2/(0.425)^2

q^2=5.23*10^-12

charge q=2.3*10^-6 C

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.