111 GLOBE 9:36 ession.masteringphysics.com 3 Exercise 27.2 MasteringPhysics 15 o

Question

111 GLOBE 9:36 ession.masteringphysics.com 3 Exercise 27.2 MasteringPhysics 15 of 15 A particle with a mass of 1.96x10-4 kg carries a negative charge of - 4.00x10-8 C. The particle is given an initial horizontal velocity that is due north and has a magnitude of 4.27x104 m/s Part A What is the magnitude of the minimum magnetic field that will keep the particle moving in the earth's gravitational field in the same horizontal, northward direction? Submit Request Answen Part B What is the direction of the minimum magnetic field? west

Explanation / Answer

a)

Force due to gravity is balanced by magnetic force

mg = qvB

=>B=mg/qv =(1.96*10-4)(9.81)/(4*10-8)(4.27*104)

B=1.126 T

b)

Direction is east

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