letter E Names (all in recitation group) PHYS 407 Recitation 5: Circular motion
ID: 1876839 • Letter: L
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letter E
Names (all in recitation group) PHYS 407 Recitation 5: Circular motion 2-2- Part I: Workbgok Chapter 4. problems 18, 19, 21, 25, 27, 29 12 pts eachl Part II: Jasmin Moghbeli is a NASA astronaut candidate undergoing training for space travel NASA uses a centrifuge to simulate the acceleration of a rocket launch. The centrifuge takes 30 s to speed up from rest to its top speed of 1 rotation every I.3 s. Ding this test, Jasmin is strapped into a seat 6.0 m from the axis. [1 pt] What is Jasmin's tangential acceleration during the first 30 s? top speed? (Each 9.8 m/s of acceleration is 1 g) the Earth (if the rocket goes straight up)? the rocket going fast enough with the acceleration in part (b) to escape Earth's gravity? a. b. 2 pts] How many g's of acceleration does she experience when the device is rotating at c. [2 pts] What is the speed of a rocket with the acceleration from part (b) at 100 km above d. [I pt] The escape velocity for objects leaving Earth 100 km away) is about 11 km/s. Is e. 12 pts] Use your conclusion in (d) and the fact that objects in low-Earth orbit (-200 km from Earth) have a tangential velocity of 7.2 km's to make a guess for how an astronaut in a rocket can escape the Earth's gravity. (FYl in a real rocket launch, astronauts usually experience a maximum of 3g's.)Explanation / Answer
(A) w = 1 x 2pi rad / 1.3 s = 4.83 rad/s
Applying wf = wi + alpha t
4.82 = 0 + 30 alpha
alpha = 0.161 rad/s^2
a_t = alpah r = 0.967 m/s^2
(B) now a_r = w^2 r = (4.83^2)(6) = 140 m/s^2
a_r = (140/9.81) g = 14.3 g
(C) vf^2 - vi^2 = 2a d
v^2 - 0 = 2(140)(100 x 10^3)
v = 5291 m/s
(D) No it is not fast enough.
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