On your wedding day you leave for the church 32.0 minutes before the ceremony is

Question

On your wedding day you leave for the church 32.0 minutes before the ceremony is to begin, which should be plenty of time since the church is only 10.0 miles away. On the way, however, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 17.0 minutes is only 5.0 mi/h.

Part A

What average speed do you need for the rest of the trip to get you to the church on time?

On your wedding day you leave for the church 32.0 minutes before the ceremony is to begin, which should be plenty of time since the church is only 10.0 miles away. On the way, however, you have to make an unanticipated stop for construction work on the road. As a result, your average speed for the first 17.0 minutes is only 5.0 mi/h.

Part A

What average speed do you need for the rest of the trip to get you to the church on time?

Explanation / Answer

average speed for the first 17.0 minutes is only 5.0 mi/h.

It means, in first 17 minutes, distance covered is

distance = speed * time

distance = 5 mi/h * 17 minutes

distance = 5/60 * 17

distance = 1.4166 miles

Therefore, we have (32-17 = 15 minutes) to travel (10 - 1.4166 = 8.5834 miles)

Therefore, new average speed should be

v = 8.5834 / 15/60

v = 34.3336 mi/h

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