(9%) Problem 9: In the figure, the net external force on the 24 kg mower is know

Question

(9%) Problem 9: In the figure, the net external force on the 24 kg mower is known to be 51 N Randomized Variables f 27 N net v=1,8 m/s Otheexpertta.com q) 50% Part (a) If the force of friction opposing the motion is 27 N, what force F (in newtons) is the person exerting on the mower? F-78 Correct 50% Part (b) Suppose the mower is moving at 1.8 m/s when the force F is removed. How far will the mower go before stopping in m? Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 10 (0% per attempt) detailed view sinO cotan) asin)acosO atan) acotan)sinh) coshOtanhO cotanh0 cosO tan() | ( 0% 0% 0% 0% 2 END Degrees Radians DEL CLEAR 4

Explanation / Answer

Part B)

Using 2nd law of motion,

Acceleration, a = Force / mass = -27 / 24 = - 1.125 m/s^2

Using 3rd equation of motion,

v^2 = u^2 + 2 as

0 = 1.8^2 + (2 x -1.125 x s)

Distance, s = 1.44 m

Comment in case any doubt please rate my answer....

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.