2. 1 points OSColPhys2016 18.8.P.055. My Notes Ask Your Teacher Point charges of

Question

2. 1 points OSColPhys2016 18.8.P.055. My Notes Ask Your Teacher Point charges of 26.0 C and 35.0 C are placed 0.650 m apart. (a) At what point (in m) along the line between them is the electric field zero? m away from the 26.0 HC charge (b) what (in N/C) is the electric field halfway between them? (Enter the magnitude.) N/C What is the direction of the electric field? along the line between the two charges toward the 35.0 HC charge along the line between the two charges toward the 26.0 HC charge There is no direction because the magnitude of the electric field is zero

Explanation / Answer

here,

q1 = 26 uC = 26 * 10^-6 C

q2 = 35 uC = 35 * 10^-6 C

r = 0.65 m

a)

let the point at which the net electric feild is zero be x

the electric feild at x , E = K * q1 /x^2 - K * q2 /(r - x)^2

as the net electric feild is zero at x

0 = K * q1 /x^2 - K * q2 /(r - x)^2

0 = 26/x^2 - 35 /(0.65 - x)^2

solving for x

x = 0.3 m

b)

the electric feild at the midpoint , E = K * q1/(r/2)^2 - K * q2 /(r/2)^2

E = 9 * 10^9 * 10^-6 /( 0.65/2)^2 * ( 26 - 35)

E = - 7.67 * 10^5 N/C

the magnitude of feild is 7.67 * 10^5 N/C

the direction of feild is along the line between the charges towards the 26 uC charge

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.