2. 1 tttatcgata ttaaaaaata tgt cagacgo ttttgaagag gaaacagt ttgcgagaaa agaa aagga
ID: 268069 • Letter: 2
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2. 1 tttatcgata ttaaaaaata tgt cagacgo ttttgaagag gaaacagt ttgcgagaaa agaa aaggaaacge gaacgacatg aattatttac 121 tottacttet acaaca 181 tttaatagga cattcacacc gttetgatca taatgaatat gaaagagatg tgt 241 cttacatgaa tcattaceca atttaccaat ercatetgog gaactaatag at ccag tatcatccac ettg acaaat gattettete tttetaatga tatgcat atcaacttag The sequence above is the first 300 nt of a cDNA (equivalent to mRNA) from a honeybee gene. a. The AT the first five amino acids of this protein. G start codon is shown in bold (beginning at position 19). Please use the genetic code to determine b. The TGA (UGA) stop codon beginning at position 34 does not cause any problems for the production of this protein. Please demonstrate that this codon is out of frame with the real codons that are being readExplanation / Answer
1) the DNA sequence is
ATG TCA GAC GCT TTT GAA GAG
the mRNA sequence is
AUG UCA GAC GCU UUU GAA GAG
protein sequence is
M S D A F E E
2) as we can see in the sequence (the bold letter) TGA or UGA is not making any codon. the codons are UUU and GAG. so the stop codon sequence is not in frame with the mRNA coding sequence.
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