1. A car, initially at rest, accelerates at 2.9 m/s 2 for a total of 5.1 s. How
ID: 1878075 • Letter: 1
Question
1. A car, initially at rest, accelerates at 2.9 m/s2 for a total of 5.1 s.
How far did it travel in this time?
2.
What acceleration does a baseball of mass 0.33 kg experience when hit by a bat exerting a force of (magnitude) 226 N on the ball?
3.
A slab of clay with a mass of 0.48 kg, moving with a speed of 5.12 m/s, hits a stationary toy car of mass 0.73 kg. If the clay hits and sticks to the car, what is the speed of the clay and car (which are now moving fused together) after impact?
4.
If you pick up a 9.5 kg object from the ground and lift it to a height of 0.57 m above the ground in 2.51 seconds, how much power is expended? (Use the value of 9.8 m/s2 for the acceleration of gravity.)
5.
What is the kinetic energy of a car with a mass of 1,072 kg if it is traveling at 8.36 m/s?
6.
What is the (average) acceleration of a vehicle which speeds up from 29 m/s to 89 m/s in 9.9 seconds?
7
How much does a 160 kg box weigh on Mars, where the acceleration of gravity is 3.71 m/s2?
8. What is the centripetal force which acts upon a 693 kg race car as it rounds a curve with a radius of curvature of 439 m at 69 m/s?
9.
an object traveling with a speed of 37.7 suddenly experiences a constant acceleration of 7.71 m/s2. What distance does this object travel in 6.48 seconds?
Explanation / Answer
1.
A car, initially at rest, accelerates at 2.9 m/s2 for a total of 5.1 s.
vi = initial velocity of the car = 0 m/s
x = displacement of the car = ?
t = time = 5.1 s
a = acceleration = 2.9 m/s2
using the equation
x = vi t + (0.5) a t2
x = 0 (5.1) + (0.5) (2.9) (5.1)2
x = 37.7 m
2)
F = force on the ball = 226 N
m = mass of the ball = 0.33 kg
a = acceleration = ?
using newton's second law
F = ma
226 = (0.33) a
a = 684.85 m/s2
5)
m = mass = 1072 kg
v = speed = 8.36 m/s
kinetic energy is given as
KE = (0.5) m v2
KE = (0.5) (1072) (8.36)2
KE = 3.75 x 104 J
6)
vi = initial speed = 29 m/s
vf = final speed = 89 m/s
t = time = 9.9 sec
a = average acceleration
average acceleration is given as
a = (vf - vi )/t
a = (89 - 29)/9.9
a = 6.06 m/s2
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