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Question

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Explanation / Answer

Problem - (10)

By evaluating the problem, we find that -

In d = 1.9 cm = 0.019 m, the ball achieves a velocity of 66 m/s. So, from this data we can find out the acceleration of the ball.

Use the expression -

v^2 = u^2 + 2*a*d

Initial velocity of the ball, u = 0

so we have -

66^2 = 0 + 2*a*0.019

=> a = 66^2 / (2*0.019) = 114631.6 m/s^2

Therefore, the average force exerted by the racket ,F = m*a = 0.040 * 114631.6 = 4585 N (Answer).

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