Question 9 2 pts The genetic map of chromosome 1 of arabidopsis is 120 m.u. with

Question

Question 9 2 pts The genetic map of chromosome 1 of arabidopsis is 120 m.u. with the centromere located approximately in the middle (see below). The T and W genes are located at the two opposite ends of the left arm, R in the center of the left arm. The most likely linkage status between these genes as determined in a genetic cross is: cen left 0 right total genetic length = 120 m. u. T-R linked, T-W unlinked T-R unlinked, T-W unlinked T-R linked, T-W linked T-R unlinked, T-w linked T-R unlinked, R-W unlinked

Explanation / Answer

According to geneticists and experimenters, it has been found that genes localized on a chromosomes should be found atleast 30 map units apart in order to assort independently. If the genes are found less than or equal to 30 map units apart, they will tend to link to each other and hence will be inherited as a single unit.

Here, it can be seen that the total length of the chromosome is 120 map units. Thus, the half of it due to centromeric location would be 60 map units. The gene R is located in the middle so it will be located 30 map units each from genes T or W. Thus, the genes T-R and W-R will tend to be linked whereas genes T-W would be unlinked.

Thus, this explanation suggests that choice 1 is correct.

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