An attacker at the base of a castle wal 3.64 m high throws a rock straight up wi

Question

An attacker at the base of a castle wal 3.64 m high throws a rock straight up with speed 7.60 m/s at a height of 1.51 m above the ground. (a) Will the rock reach the top of the wall? Yes No (b) If so, what is the rock's speed at the top? If not, what initial speed must the rock have to reach the top? 3.9m/s (c) Find the change in the speed of a rock thrown straight down from the top of the wall at an initial speed of 7.60 m's and moving between the same two points 2.200 × Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error m s

Explanation / Answer

(c)

Let:

u be the initial projection speed,

v be the speed at distance h below.

v^2 = u^2 + 2gh ...(2)

v = sqrt[ 7.60^2 + 2 * 9.81(3.64 - 1.51) ]

= 9.98 m/s.

Change in speed = 9.98 – 7.60 = 2.38 m/s

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