please show calculation in a separate page. 2. You are using a 2.5 m lever to li

Question

please show calculation in a separate page.

2. You are using a 2.5 m lever to lift a rock with a mass of 100 kg. The effort to lift the rock is the force with which you push down on the other end of the lever. The forces (the mg of the rock, and FE) balance according to the equation: FR dR FEdE, where F is the weight of the rock, dR is the distance from the rock to the pivot, FE is your pushing force, and de is the distance from the end of the lever where you push to the pivot. If dR is 40 cm, what is the force of your effort? FE- How much mass on the opposite end of the lever would balance the weight of the rock?kg

Explanation / Answer

2] FRdR = FEdE

(100 x 9.8) x 2.5 = FE(0.4)

=> FE = 6125 N

this is the force of effort. For the mass,

m = FE/9.8 = 625 kg

this is the mass which will balance the weight of the rock.

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