Problem 21.75 Constants 1 Periodic Table Part A A parallelplate capacitor is cha

Question

Problem 21.75 Constants 1 Periodic Table Part A A parallelplate capacitor is charged to 5000 V A proton is fired into the center of the capacitor at a speed of 2 5-105 m/s as shown in (Figure 1). The proton i deflected while inside the capacitor, and the plates are long enough that the proton will hit one of them before emerging from the far side of the capacitor What is the impact speed of the proton? Express your answer with the appropriate units. Ey= 1 Value Units Submit Provide Feedback Figure 1 of1 Vo

Explanation / Answer

Potential energy initally at entrance of proton

U= qV= 1.6*10^-19*(5000/2)

Considering conservation of energy

0.5*1.67*10^-27* (v^2- (2.5*10^5)^2)= 1.6*10^-19*2500

V= 7.36*10^5 m/s

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Comment in case any doubt.. good luck

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