(b) An electron is now fired in the same direction from the same position. What
ID: 1880872 • Letter: #
Question
(b) An electron is now fired in the same direction from the same position. What is its change in electric potential energy if it reaches x = 11.90 cm? 3.14e-17 (c) If the direction of the electric field is reversed and an electron is released from rest at x-3.10 cm, by how much has its electric potential energy changed when it reachesx-6.90 cm? -7.006e-18 X Your response differs from the correct answer by more than 10%. Double check your calculations. EXERCISE HINTS: GETTING STARTED II'M STUCK! Find the change in electric potential energy associated with the electron in part (b) as it goes on from x 0.119 to x =-0.019 m. (Note that the electron must turn around and go back at some point. The location of the turning point is unimportant, because changes in potential energy depend only on the end points of the path.) APE-3.33e-17Explanation / Answer
Yiu didn't give the value of electric field, which was given at the beginning of the question. I am giving you in terms of 'E', put the value of E in the equation and solve.
In case any doubt, feel free to ask ...
change in electric potential energy:
PE = -(1.6 x 10^-19 C) (E) (-0.019 - 0.119)
= ..... J (Ans)
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