GINEERING PHYSICS II Fall 2018 EXAM I For the following problems, show all your
ID: 1880940 • Letter: G
Question
GINEERING PHYSICS II Fall 2018 EXAM I For the following problems, show all your work, starting from Coulomb's Law or Gauss's Law, for full credit. ca-8.85 × 10 12C"/N-m? (25 points) Two charges are placed near each other. The first charge h1.5uC and is placed at position ri-(2,0). The second charge has q2-40 and is at position r2-(1,1). Note that k -8.99 x 10 Nm/c (a) Find the magnitude of the electrostatic force between the two charges. (b) Find the electric field (E) due to these two charges at position r (0,0) (c) Find the electric potential V at r (0,0).Explanation / Answer
Given that,
q1 = 1.5 uC
q2 = 4 uC
(a)
Electrostatic force b/w both the charges,
F = kq1q2 / r^2
here, r^2 = (1 + 1) = 2
F = 8.99*10^9*1.5*10^(-6)*4*10^(-6) / 2
F = 0.0269 N
(b)
Electric field at origion,
E = kq1 / r1^2 + kq2 / r2^2
here, r1 = 2 m
r2^2 = 1^2 + 1^2 = 2
E = 8.99*10^9*10^(-12) * [1.5 / 2^2 + 4 / 2]
E = 0.0213 N/C
(c)
electric potential at origin,
V = kq1 / r1 + kq2 / r2
V = 8.99*10^9*10^(-12) * [1.5 / 2 + 4 / 1.414]
V = 0.0321 V
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