Exercise 23.13-Enhanced - with Solution 3 of 7 Constants PartA A small particle

Question

Exercise 23.13-Enhanced - with Solution 3 of 7 Constants PartA A small particle has charge-5.20 C and mass 2.30x10-4 kg. It moves from point A, where the electric potential is VA-240 V, to point B, where the electric potential VB 620 V is greater than the potential at point A. The electric force is the only force acting on the particle. The particle has a speed of 3.30 m/s at point A What is its speed at point B? m/s You may want to review (Pages 759- 765) For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Electric force and electric potential Submit Request Answer Part B Is it moving faster or slower at B than at A? Faster Slower Submit Request Answer

Explanation / Answer

part B) let the speed at point B is v

Using conservation of mechanical energy

total energy at A = total energy at B

0.50 * 2.3 *10^-4 * 3.3^2 + (-5.2 * 10^-6 * 240) = 0.50 * 2.3 *10^-4 * v^2 + (-5.2 * 10^-6 * 620)

solving for v

v = 5.3 m/s

the speed of charge at point B is 5.3 m/s

part B)

it is moving faster at B than A

Faster

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