Need help with question 5 and 6 please 4:43 PM 21% a quest The graph shows the v

Question

Need help with question 5 and 6 please
4:43 PM 21% a quest The graph shows the velocity e as a function 9 of time t for an object moving in a straight line. 005 (part 1 of 2) 10.0 points A runner is jogging in a straight line at a steady 8.2 km/hr. When the runner is Which graph shows the corresponding dis L 2.2 km from the finish line, a bird begins placement z as a function of time t for the flying straight from the runner to the finish line at t 24.6 km/hr (3 times as fast as the runner). When the bird reaches the finish line, it turns around and flies directly back to same time interval? 1. None of these graphs is correct the runner pallares (kmp3667)-Homework 2, ld motion 18-19 REV- marder - (Brown J302K1819 4) 2 position finish line What cumulative distance does the bird travel? Even though the bird is a dodo, as- sume that it occupies only one point in space (a "zero" length bird), travels in a straight line, and that it can turn without loss of speed time Answer in units of km. Which is true? 006 (part 2 of 2) 10.0 points 1. Somewhere before time tB, both trains After this first encounter, the bird then turns have the same acceleration. around and flies from the runner back to the finish line, turns around again and flies back 2. Both trains speed up all the time. to the runner. The bird repeats the back and forth trips until the runner reaches the finish 3. Both trains have the same velocity at line some time before t B How far does the bird travel from the be- ginning (including the distance traveled to the first encounter)? he time interval from t O to t-t train B covers more distance than trainA Answer in units of km. 5. At time tB, both trains have the same 010 10.0 points data gathered from an automobile fitted with 007 10.0 points velocity A reconnaissance plane flies 593 km away from its base at s06 m/s, then flies back to its base at 1209 m/s. e plots show What is its average speed?

Explanation / Answer

(5) Distance from the finish line (S) = 2.2 km
Speed of bird (VB) = 24.6 Km/hr
Time taken by the bird to cover this distance (t) = 2.2/24. 6= 0.089 hr
Distance coverd by the runner in this time (s) = 8.2*0.089 = 0.733 km
Hence when bird return from the finish line , then the distance between the runner and the bird will be
=2.2 - 0.733 = 1.467 km
Now time taken to cover this relative distance (t2) = 1.467/(VR+VB) = 1.467/(8.2+24.6) =0.0447 hr
Hence the distance coverd by the bird in this time (s2) = 0.0447*24.6 = 1.1 km
hence the total distance covered by the bird = 2.2+1.1 = 3.3 km
Hence the cumulative distance covered by the bird will be 3.3 km

(6)Distance from the finish line (S) = 2.2 Km
Speed of the runner (VR) = 8.2 km/hr
Now the time taken by the runner in covering this distance (t) =S/VR = 2.2/8.2 = 0.268 hr
Now the speed of the bird (VB) = 24.6 Km/hr
Distance covered by the bird in this time (s) = 24.6*0.268 = 6.593 km
Hence the cumulative distance covered by the bird would be 6.593 Km .

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