3. A ball thrown is thrown at an angle of 35.0 above the horizontal at 120 m/s f

Question

3. A ball thrown is thrown at an angle of 35.0 above the horizontal at 120 m/s from the top of a 18.0 m high cliff. How far from the base of the cliff does the ball hit the ground? A cannon fires cannonballs from the top of a castle wall. The first cannonball is fired at a speed of 60.0 m/s and at an angle of 22.5 above the horizontal. A second cannonball that was accidentally dropped hits the moat below in 1.15 s. How far from the castle wall does the fired (first) cannonball hit the ground? 4.

Explanation / Answer

here,

3)

theta = 35 degree

speed , u = 12 m/s

h0 = - 18 m

let the time taken for the ball in air be t

h0 = u * sin(theta) * t -0.5 * g * t^2

- 18 = 12 * sin(35) * t -0.5 * 9.81 * t^2

solving for t

t = 2.74 s

the horizontal distance , x = u * cos(theta) * t

x = 12 * cos(35) * 2.74 m

x = 26.9 m

4)

time taken by the dropped ball , t1 = 1.15 s

the height of castle wall , h = 0 + 0.5 * g * t1^2

h = 0 + 0.5 * 9.81 * 1.15^2 m

h = 6.49 m

for the Cannon ball

let the time taken be t2

- h = u * sin(theta) * t2 - 0.5 * g * t2^2

- 6.49 = 60 * sin(22.5) * t2 - 0.5 * 9.81 * t2^2

solving for t2

t2 = 1.71 s

the horizontal distance , x = u * cos(theta) * t2

x = 60 * cos(22.5) *

x = 60 * cos(22.5) * 1.71 m

x = 94.8 m

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