An albino snake mates with a brown snake and all of the F1 progeny are black. A

Question

An albino snake mates with a brown snake and all of the F1 progeny are black. A mating between two F1 results in a ratio of 9 black:3 brown: 4 albino. Which of the following is correct? Select one: O a. The genes for black and albinism/brown interact by recessive epistasis, the gene for black is epistatic O b. The genes for black and brown/albanism interact by dominant epistasis, the gene for black is epistatic Oc. The genes for brown and albinism/black interact by recessive epistasis, the gene for brown is epistatic d. The genes for black/brown and albinism interact by dominant epistasis, the gene for albinism is epistatic O e. The genes for black/brown and albinism interact by recessive epistasis, the gene for albinism is epistatic

Explanation / Answer

Answer:
Option E is correct.

Explanation:
Phenotypic ratio of dominant epistasis = 12:3:1
Phenotypic ratio of recessive epistasis = 9:3:4

In recessive epistasis, a homozygous recessive condition at one locus masks the effects of either allele of the second locus.

Parental cross: Albino X Brown
F1: All black
F2: 9 black:3 brown : 4 albino

The recessive allele is epistatic to other genes when in homozygous condition.

Albino -----> Brown ------> Black

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